Advertisements
Advertisements
प्रश्न
A consumer uses 4 lamps of 60 watt, 2 lamps of 40 watt, and 2 lamps of 100 watt. All these are used for 6 hour daily. Find the total bill for 30 days when the rate of energy is 75 paise per unit and the meter rent is Rs. 1.
Advertisements
उत्तर
Total power consumption of 4 lamps of 60 watt each = 60 × 4 = 240 W
Total power consumption of 2 lamps of 40 watt each = 40 × 2 = 80 W
Total power consumption of 2 lamps of 100 watt each = 100 × 2 = 200 W.
∴ Total power consumption = (240 + 80 + 200) = 520 W
∴ Total watt-hour for 6 hours a day for 30 days = 520 × 6 × 30 = 93600 watt-hour
Hence, kilowatt-hour =`93600/1000 = 93.6` kWh
Cost of electric energy at 75 p.per kWh =`(93.6 xx 75)/100 = 70.20`
∴ Total cost = Rs. 70.20 + Rs. 1.0 (Meter rent)
= Rs. 71.20
संबंधित प्रश्न
Which uses more energy: a 250 W TV set in 1 hour or a 1200 W toaster in 10 minutes?
Calculate the cost of operating a heater of 500 W for 20 hours at the rate of Rs 3.90 per unit.
When an electric lamp is connected to 12 V battery, it draws a current of 0.5 A. The power of the lamp is:
(a) 0.5 W
(b) 6 W
(c) 12 W
(d) 24 W
Name the S.I. unit of electrical energy. How is it related to Wh?
Two lamps, one rated 220 V, 50 W and the other rated 220 V, 100 W, are connected in serieswith mains of 220 V. Explain why does the 50 W lamp consume more power
‘The current rating of a fuse is 5A’. Comment on this statement.
An electric heater is rated 220 V, 550 W. Electrical energy is also measured in kWh. What do you understand by a kilo-watt-hour?
Three 250 W heaters are connected in parallel to a 100 V supply, Calculate the energy supply in kWh to the three heaters in 5 hour.
I ampere of current is passed through a resistor of resistance R ohm for time t second. Obtain expression for
(i) the electrical energy, and
(ii) the electrical power spent.
