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प्रश्न
A bulb is connected to a battery of p.d. 4 V and internal resistance 2.5 Ω . A steady current of 0.5 A flows through the circuit. Calculate:
The resistance of the bulb
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उत्तर
Given ,
Voltage , V = 4 V
Resistance of the battery , RB = 2.5 Ω
Current , I = 0.5 A
Total resistance , R = 8 Ω
Resistance of the battery , RB = 2.5 Ω
Resistance of the blub, Rb = 8 - 2.5 Ω = 5.5 Ω
संबंधित प्रश्न
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Following graph was plotted between V and I values:
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What conclusion do you draw from these values?
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| ‘A’ Group | ‘B’ Group |
| 1. Free electrons | a. V/R |
| 2. Current | b. Increases the resistance in the circuit |
| 3. Resistivity | c. Weakly attached |
| 4. Resistances in series | d. VA/LI |
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1 kWh = _________ J
