Advertisements
Advertisements
प्रश्न
A 10 g bullet travelling at 200 m/s strikes and remains embedded in a 2 kg target which is originally at rest but free to move. At what speed does the target move off ?
Advertisements
उत्तर
Here,
Mass of the bullet, m = 10 g = 0.01 kg
Velocity of the bullet, v = 200 m/s
Mass of the target, M = 2 kg
Mass of the (target+bullet) after hitting = V (say)
Momentum of the system before hitting = (0.01)(200) + (2)(0) = 2
Momentum of the system after hitting = (2 + 0.01)V
(after hitting the bullet sticks to the target)
Now,
By law of conservation of momentum,
Momentum of the system before hitting = Momentum of the system after hitting
⇒ 2 = (2 + 0.01)V
⇒ V = 0.995 m/s
This is the velocity with which the bullet and the target moves after hitting.
APPEARS IN
संबंधित प्रश्न
Two objects, each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m s−1 before the collision during which they stick together. What will be the velocity of the combined object after collision?
Akhtar, Kiran and Rahul were riding in a motorcar that was moving with a high velocity on an expressway when an insect hit the windshield and got stuck on the windscreen. Akhtar and Kiran started pondering over the situation. Kiran suggested that the insect suffered a greater change in momentum as compared to the change in momentum of the motorcar (because the change in the velocity of the insect was much more than that of the motorcar). Akhtar said that since the motorcar was moving with a larger velocity, it exerted a larger force on the insect. And as a result the insect died. Rahul while putting an entirely new explanation said that both the motorcar and the insect experienced the same force and a change in their momentum. Comment on these suggestions.
Two billiard balls, each of mass 0.05 kg, moving in opposite directions with speed 6 ms-1collide and rebound with the same speed. What is the impulse imparted to each ball due to the other?
Explain the meaning of the following equation : .
p = m x v
where symbols have their usual meanings.
What is the momentum in kg.m/s of a 10 kg car travelling at (a) 5 m/s (b) 20 cm/s, and (c) 36 km/h ?
Calculate the change in momentum of a body weighing 5 kg when its velocity decreases from 20 m/s to 0.20 m/s.
Which physical quantity corresponds to the rate of change of momentum ?
State the relation between the momentum of a body and the force acting on it.
The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s.
(a) What is the momentum before the force acts ?
(b) What is the momentum after the force acts ?
(c) What is the gain in momentum per second ?
(d) What is the value of the force ?
A girl riding a bicycle along a straight road with a speed of 5 ms–1 throws a stone of mass 0.5 kg which has a speed of 15 ms–1 with respect to the ground along her direction of motion. The mass of the girl and bicycle is 50 kg. Does the speed of the bicycle change after the stone is thrown? What is the change in speed, if so?
