Advertisements
Advertisements
प्रश्न
1×5 divisible by 3?
योग
Advertisements
उत्तर
1×5 is divisible by 3
⇒ 1 + x + 5 is a multiple of 3
⇒ 6 + x = 0, 3, 6, 9,
⇒ x = -6, -3, 0, 3, 6, 9
Since, x is a digit
x = 0, 3, 6 or 9
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Find the remainder when 51439786 is divided by 3. Do this without performing actual division.
Find which of the following numbers are divisible by 3:
(i) 261
(ii) 777
(iii) 6657
(iv) 2574
28×6 a multiple of 3?
5 × 555 a multiple of 9?
Check the divisibility of 15287 by 3.
Find the dates of any month in a calendar which are divisible by both 2 and 3.
Let abc be a three digit number. Then abc + bca + cab is not divisible by ______.
Number of the form 3N + 2 will leave remainder 2 when divided by 3.
What is the rule to check if a number is divisible by 3?
The digit sum of 91 is 10. Therefore, 91 is:
