Advertisements
Advertisements
प्रश्न
1×5 divisible by 3?
Advertisements
उत्तर
1×5 is divisible by 3
⇒ 1 + x + 5 is a multiple of 3
⇒ 6 + x = 0, 3, 6, 9,
⇒ x = -6, -3, 0, 3, 6, 9
Since, x is a digit
x = 0, 3, 6 or 9
APPEARS IN
संबंधित प्रश्न
If 21y5 is a multiple of 9, where y is a digit, what is the value of y?
Find the remainder when 51439786 is divided by 3. Do this without performing actual division.
Which of the following statement is true?
If a number is divisible by 3, it must be divisible by 9.
Which of the following statement is true?
If a number is divisible by 9, it must be divisible by 3.
31×5 divisible by 3?
7×34 divisible by 9?
Find the dates of any month in a calendar which are divisible by both 2 and 3.
The least number that should be added to 57 so that the sum is exactly divisible by 2, 3, 4 and 5 is __________
The digit sum of 91 is 10. Therefore, 91 is:
Among 63, 872, and 552, how many numbers are divisible by 3?
