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प्रश्न
31×5 divisible by 3?
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उत्तर
31×5 is divisible by 3
⇒ 3 + 1 + x + 5 is a multiple of 3
⇒ 9 + x = 0, 3, 6, 9,
⇒ x = -9, -6, -3, 0, 3, 6, 9,
Since, x is a digit
x = 0, 3, 6 or 9
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