Advertisements
Advertisements
प्रश्न
If 24x is a multiple of 3, where x is a digit, what is the value of x?
(Since 24x is a multiple of 3, its sum of digits 6 + x is a multiple of 3; so 6 + x is one of these numbers: 0, 3, 6, 9, 12, 15, 18…. But since x is a digit, it can only be that 6 + x = 6 or 9 or 12 or 15. Therefore, x = 0 or 3 or 6 or 9. Thus, x can have any of four different values)
Advertisements
उत्तर
Since 24x is a multiple of 3, the sum of its digits is a multiple of 3.
Sum of digits of 24x = 2 + 4 + x = 6 + x
Hence, 6 + x is a multiple of 3.
This is possible when 6 + x is any one of these numbers 0, 3, 6, 9, and so on …
Since x is a single digit number, the sum of the digits can be 6 or 9 or 12 or 15 and thus, the value of x comes to 0 or 3 or 6 or 9 respectively.
Thus, x can have its value as any of the four different values 0, 3, 6, or 9
संबंधित प्रश्न
If 31z5 is a multiple of 9, where z is a digit, what is the value of z? You will find that there are two answers for the last problem. Why is this so?
If x is a digit of the number \[\overline {{66784x}}\] such that it is divisible by 9, find possible values of x.
Given that the number \[\overline{{67y19}}\] is divisible by 9, where y is a digit, what are the possible values of y?
31×5 divisible by 3?
5 × 555 a multiple of 9?
There are some flowering trees in a garden. Each tree bears many flowers with the same number printed on it. Three children took a basket each to pick flowers. Each basket has one of the numbers, 3, 4 or 9 on it. Each child picks those flowers which have numbers divisible by the number on his or her basket. He/She takes only 1 flower from each tree. Can you tell which numbers the flowers in each basket will have?

The least number that should be added to 57 so that the sum is exactly divisible by 2, 3, 4 and 5 is __________
Let abc be a three-digit number. Then abc – cba is not divisible by ______.
Number of the form 3N + 2 will leave remainder 2 when divided by 3.
The digit sum of 91 is 10. Therefore, 91 is:
