Balbharati solutions for Mathematics 2 Geometry 10th Standard SSC Maharashtra State Board chapter 6 - Trigonometry [Latest edition]

If \[\sin\theta = \frac{7}{25}\], find the values of cosθ and tan​θ.

If \[\tan \theta = \frac{3}{4}\], find the values of sec​θ and cos​θ

If \[\cot\theta = \frac{40}{9}\], find the values of cosecθ and sinθ.

If tanθ = 1 them, find the values of

Prove that:
\[\frac{\sin^2 \theta}{\cos\theta} + \cos\theta = \sec\theta\]

Prove that:

\[\cos^2 \theta\left( 1 + \tan^2 \theta \right) = 1\]

Prove that:

Prove that:

Prove that:

Prove that:

Prove that:
\[\sec^4 \theta - \cos^4 \theta = 1 - 2 \cos^2 \theta\]

Prove that:

Prove that:
If \[\tan\theta + \frac{1}{\tan\theta} = 2\], then show that \[\tan^2 \theta + \frac{1}{\tan^2 \theta} = 2\]

Prove that:

Prove that:

Prove that:

From the top of a lighthouse, an observer looking at a ship makes angle of depression of 60°. If the height of the lighthouse is 90 metre, then find how far the ship is from the lighthouse.

A kite is flying at a height of 60 m above the ground. The string attached to the kite is tied at the ground. It makes an angle of 60° with the ground. Assuming that the string is straight, find the length of the string.

Choose the correct alternative answer for the following question.
sin \[\theta\] cosec \[\theta\]= ?

Choose the correct alternative answer for the following question.
cosec 45^° =?

Choose the correct alternative answer for the following question.

1 + tan² \[\theta\]  = ?

Choose the correct alternative answer for the following question.

If \[\sin\theta = \frac{11}{61}\], find the values of cosθ using trigonometric identity.

If \[\sec\theta = \frac{13}{12}\], find the values of other trigonometric ratios.

Prove the following.
secθ (1 – sinθ) (secθ + tanθ) = 1

Prove the following.
(secθ + tanθ) (1 – sinθ) = cosθ

Prove the following.
sec²θ + cosec²θ = sec²θ × cosec²θ 

Prove the following.
cot²θ – tan²θ = cosec²θ – sec²θ

Prove the following.

tan⁴θ + tan²θ = sec⁴θ - sec²θ

Prove the following.

Prove the following.
sec⁶x – tan⁶x = 1 + 3sec²x × tan²x

Prove the following.
\[\frac{\tan\theta}{sec\theta + 1} = \frac{sec\theta - 1}{\tan\theta}\]

Prove the following.

Prove that `(sinθ - cosθ + 1)/(sinθ + cosθ - 1) = 1/(secθ - tanθ)`