HSC Arts Class 11 - Tamil Nadu Board of Secondary Education Question Bank Solutions for Mathematics

Justify the trueness of the statement:
“An element of a set can never be a subset of itself.”

For a set A, A × A contains 16 elements and two of its elements are (1, 3) and (0, 2). Find the elements of A

Let A and B be two sets such that n (A) = 3 and n(B) = 2. If (x, 1), (y, 2), (z, 1) are in A × B, find A and B, where x, y, z are distinct elements

If A × A has 16 elements, S = {(a, b) ∈ A × A : a < b} ; (−1, 2) and (0, 1) are two elements of S, then find the remaining elements of S

Choose the correct alternative:

If A = {(x, y) : y = sin x, x ∈ R} and B = {(x, y) : y = cos x, x ∈ R} then A ∩ B contains

Choose the correct alternative:

Let A and B be subsets of the universal set N, the set of natural numbers. Then A' ∪ [(A ∩ B) ∪ B'] is

Choose the correct alternative:

The number of students who take both the subjects Mathematics and Chemistry is 70. This represents 10% of the enrollment in Mathematics and 14% of the enrollment in Chemistry. The number of students take at least one of these two subjects, is

If x+y = 5 and x-y= 3 then, Value of x

Integration is the reverse process of

Data processing is done by

If 62 = 34 + 4x what is x?

Given the demand function q = 150 − 3p, derive a function for MR.

Find the average cost function where TC = 60 + 10x +15x²

Suppose the price p and quantity q of a commodity are related by the equation q = 30 - 4p - p2 find

1. ed at p = 2
2. MR

Solve for x quantity demanded if 16x − 4 = 68 + 7x.

Write the set {−1, 1} in set builder form

By taking suitable sets A, B, C, verify the following results:

A × (B ∩ C) = (A × B) ∩ (A × C)

By taking suitable sets A, B, C, verify the following results:

A × (B ∪ C) = (A × B) ∪ (A × C)

By taking suitable sets A, B, C, verify the following results:

(A × B) ∩ (B × A) = (A ∩ B) × (B ∩ A)

By taking suitable sets A, B, C, verify the following results:

C − (B − A) = (C ∩ A) ∪ (C ∩ B')