SSLC (English Medium) Class 10 - Tamil Nadu Board of Secondary Education Question Bank Solutions for Mathematics

The function ‘t’ which map temperature in Celsius (C) into temperature in Fahrenheit (F) is defined by t(C) = F where F = `9/5` C + 32. Find, t(0)

The function ‘t’ which map temperature in Celsius (C) into temperature in Fahrenheit (F) is defined by t(C) = F where F = `9/5` C + 32. Find, t(28)

The function ‘t’ which map temperature in Celsius (C) into temperature in Fahrenheit (F) is defined by t(C) = F where F = `9/5` C + 32. Find, t(– 10)

The function ‘t’ which map temperature in Celsius (C) into temperature in Fahrenheit (F) is defined by t(C) = F where F = `9/5` C + 32. Find, the value of C when t(C) = 212

The function ‘t’ which map temperature in Celsius (C) into temperature in Fahrenheit (F) is defined by t(C) = F where F = `9/5` C + 32. Find, the temperature when the Celsius value is equal to the Fahrenheit value

Multiple Choice Question :

If {(a, 8), (6, b)} represent an identity function, then the value of a and b are respectively

Write the domain of the following real function:

f(x) = `(2x + 1)/(x - 9)`

Write the domain of the following real function:

p(x) = `(-5)/(4x^2 + 1)`

Write the domain of the following real function:

g(x) = `sqrt(x - 2)`

Write the domain of the following real function:

h(x) = x + 6

Graph the following quadratic equation and state their nature of solution

x² – 9x + 20 = 0

Graph the following quadratic equation and state their nature of solution

x² – 4x + 4 = 0

Graph the following quadratic equation and state their nature of solution

x² + x + 7 = 0

Graph the following quadratic equation and state their nature of solution

x² – 9 = 0

Graph the following quadratic equation and state their nature of solution

x² – 6x + 9 = 0

Graph the following quadratic equation and state their nature of solution

(2x – 3) (x + 2) = 0

Draw the graph of y = x² – 4 and hence solve x² – x – 12 = 0

Draw the graph of y = x² + x and hence solve x² + 1 = 0

Draw the graph of y = x² + 3x + 2 and use it to solve x² + 2x + 1 = 0

Draw the graph of y = x² + 3x – 4 and hence use it to solve x² + 3x – 4 = 0