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Minimize z = 2x + 4y is subjected to 2x + y ≥ 3, x + 2y ≥ 6, x ≥ 0, y ≥ 0 show that the minimum value of z occurs at more than two points
Concept: undefined >> undefined
Maximize z = −x + 2y subjected to constraints x + y ≥ 5, x ≥ 3, x + 2y ≥ 6, y ≥ 0 is this LPP solvable? Justify your answer.
Concept: undefined >> undefined
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x − y ≤ 1, x − y ≥ 0, x ≥ 0, y ≥ 0 are the constant for the objective function z = x + y. It is solvable for finding optimum value of z? Justify?
Concept: undefined >> undefined
If `int 1/(x + x^5)` dx = f(x) + c, then `int x^4/(x + x^5)`dx = ______
Concept: undefined >> undefined
`int ("e"^x(x - 1))/(x^2) "d"x` = ______
Concept: undefined >> undefined
`int sqrt(1 + sin2x) dx`
Concept: undefined >> undefined
`int (sin4x)/(cos 2x) "d"x`
Concept: undefined >> undefined
`int ("e"^(3x))/("e"^(3x) + 1) "d"x`
Concept: undefined >> undefined
`int (2 + cot x - "cosec"^2x) "e"^x "d"x`
Concept: undefined >> undefined
`int "e"^x[((x + 3))/((x + 4)^2)] "d"x`
Concept: undefined >> undefined
`int ("e"^(2x) + "e"^(-2x))/("e"^x) "d"x`
Concept: undefined >> undefined
`int x^x (1 + logx) "d"x`
Concept: undefined >> undefined
`int 1/(xsin^2(logx)) "d"x`
Concept: undefined >> undefined
`int sqrt(x) sec(x)^(3/2) tan(x)^(3/2)"d"x`
Concept: undefined >> undefined
`int (cos2x)/(sin^2x) "d"x`
Concept: undefined >> undefined
`int x/(x + 2) "d"x`
Concept: undefined >> undefined
`int cos^7 x "d"x`
Concept: undefined >> undefined
`int(log(logx))/x "d"x`
Concept: undefined >> undefined
