HSC Science (General) 12th Standard Board Exam - Maharashtra State Board Question Bank Solutions for Mathematics and Statistics

Differentiate the following w.r.t. x : `"cosec"^-1((1)/(4cos^3 2x - 3cos2x))`

Differentiate the following w.r.t. x : `tan^-1[(1 + cos(x/3))/(sin(x/3))]`

Differentiate the following w.r.t. x : `cot^-1((sin3x)/(1 + cos3x))`

Differentiate the following w.r.t. x : `tan^-1((cos7x)/(1 + sin7x))`

Differentiate the following w.r.t. x : `tan^-1(sqrt((1 + cosx)/(1 - cosx)))`

Differentiate the following w.r.t.x:

tan^–1 (cosec x + cot x)

Differentiate the following w.r.t. x :

`cot^-1[(sqrt(1 + sin  ((4x)/3)) + sqrt(1 - sin  ((4x)/3)))/(sqrt(1 + sin  ((4x)/3)) - sqrt(1 - sin  ((4x)/3)))]`

Differentiate the following w.r.t. x : `sin^-1((4sinx + 5cosx)/sqrt(41))`

Differentiate the following w.r.t. x : `cos^-1((sqrt(3)cosx - sinx)/(2))`

Differentiate the following w.r.t. x : `sin^-1((cossqrt(x) + sinsqrt(x))/sqrt(2))`

Differentiate the following w.r.t. x : `cos^-1((3cos3x - 4sin3x)/5)`

Differentiate the following w.r.t. x :

`cos^-1[(3cos(e^x) + 2sin(e^x))/sqrt(13)]`

Differentiate the following w.r.t. x : `"cosec"^-1[(10)/(6sin(2^x) - 8cos(2^x))]`

Differentiate the following w.r.t. x :

`cos^-1((1 - x^2)/(1 + x^2))`

Differentiate the following w.r.t. x : `tan^-1((2x)/(1 - x^2))`

Differentiate the following w.r.t. x : `sin^-1((1 - x^2)/(1 + x^2))`

Differentiate the following w.r.t. x : `sin^-1(2xsqrt(1 - x^2))`

Differentiate the following w.r.t. x : cos^–1(3x – 4x³)

Differentiate the following w.r.t. x : `cos^-1((e^x -  e^(-x))/(e^x +  e^(-x)))`

Differentiate the following w.r.t. x :

`cos^-1  ((1 - 9^x))/((1 + 9^x)`