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HSC Commerce (English Medium) 12th Standard Board Exam - Maharashtra State Board Question Bank Solutions for Mathematics and Statistics

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Mathematics and Statistics
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Without using truth table show that

(p ∨ q) ∧ (~ p ∨ ~ q) ≡ (p ∧ ~ q) ∨ ( ~ p ∧ q)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

If p ↔ q and p → q both are true, then find truth values of the following with the help of activity

p ˅ q

p ↔ q and p → q both are true if p and q has truth value `square`, `square` or `square`, `square`.

p ˅ q

i. If both p and q are true, then p ˅ q = `square` ˅ `square` = `square`

ii. If both p and q are false, then p ˅ q = `square` ˅ `square` = `square`

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

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If p ↔ q and p → q both are true, then find truth values of the following with the help of activity

p ˄ q

p ↔ q and p → q both are true if p and q has truth value `square`, `square` or `square`, `square`

p ˄ q

i. If both p and q are true, then p ˄ q = `square` ˄ `square` = `square`

ii. If both p and q are false, then p ˄ q = `square` ˄ `square` = `square`

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Given following statements
p: 9 × 5 = 45
q: Pune is in Maharashtra
r: 3 is the smallest prime number

Write truth values by activity

i) (p ˄ q) ˄ r = `(square` ˄ `square)` ˄ `square`

= `square` ˄ `square`

= `square`

ii) ~ ( p ˄ r ) = `~(square` ˄ `square)`

= `~ square`

= `square`

iii) p → q = `square → square`

= `square`

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

If y = `1/sqrt(3x^2 - 2x - 1)`, then `("d"y)/("d"x)` = ?

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Choose the correct alternative:

If y = `root(3)((3x^2 + 8x - 6)^5`, then `("d"y)/("d"x)` = ?

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Choose the correct alternative:

If y = `x^(sqrt(x))`, then `("d"y)/("d"x)` = ?

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

If y = (5x3 – 4x2 – 8x)9, then `("d"y)/("d"x)` is ______

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

If y = x10, then `("d"y)/("d"x)` is ______

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

If y = `("e")^((2x + 5))`, then `("d"y)/("d"x)` is ______

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

If y = x2, then `("d"^2y)/("d"x^2)` is ______

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

State whether the following statement is True or False:

If y = ex, then `("d"y)/("d"x)` = ex 

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

State whether the following statement is True or False:

If x2 + y2 = a2, then `("d"y)/("d"x)` = = 2x + 2y = 2a

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

State whether the following statement is True or False:

If y = ex, then `("d"^2y)/("d"x^2)` = ex 

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"y)/("d"x)`, if y = (6x3 – 3x2 – 9x)10 

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"^2y)/("d"x^2)`, if y = `"e"^((2x + 1))`

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

Find `("d"y)/("d"x)`, if y = `root(5)((3x^2 + 8x + 5)^4`

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

y = (6x4 – 5x3 + 2x + 3)6, find `("d"y)/("d"x)`

Solution: Given,

y = (6x4 – 5x3 + 2x + 3)6 

Let u = `[6x^4 - 5x^3 + square + 3]`

∴ y = `"u"^square`

∴ `("d"y)/"du"` = 6u6–1

∴ `("d"y)/"du"` = 6(  )5 

and `"du"/("d"x) = 24x^3 - 15(square) + 2`

By chain rule,

`("d"y)/("d"x) = ("d"y)/square xx square/("d"x)`

∴ `("d"y)/("d"x) = 6(6x^4 - 5x^3 + 2x + 3)^square xx (24x^3 - 15x^2 + square)`

[3] Differentiation
Chapter: [3] Differentiation
Concept: undefined >> undefined

The slope of the tangent to the curve y = x3 – x2 – 1 at the point whose abscissa is – 2, is ______.

[4] Applications of Derivatives
Chapter: [4] Applications of Derivatives
Concept: undefined >> undefined

Choose the correct alternative:

Slope of the normal to the curve 2x2 + 3y2 = 5 at the point (1, 1) on it is 

[4] Applications of Derivatives
Chapter: [4] Applications of Derivatives
Concept: undefined >> undefined
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