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HSC Arts (English Medium) 12th Standard Board Exam - Maharashtra State Board Question Bank Solutions for Mathematics and Statistics

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Mathematics and Statistics
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If A = {2, 3, 4, 5, 6}, then which of the following is not true?

(A) ∃ x ∈ A such that x + 3 = 8

(B) ∃ x ∈ A such that x + 2 < 5

(C) ∃ x ∈ A such that x + 2 < 9

(D) ∀ x ∈ A such that x + 6 ≥ 9

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Rewrite the following statement without using if ...... then.

If a man is a judge then he is honest.

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

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Rewrite the following statement without using if ...... then.

It 2 is a rational number then `sqrt2` is irrational number.

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Rewrite the following statement without using if ...... then.

It f(2) = 0 then f(x) is divisible by (x – 2).

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Without using truth table prove that:

(p ∨ q) ∧ (p ∨ ∼ q) ≡ p

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Without using truth table prove that:

(p ∧ q) ∨ (∼ p ∧ q) ∨ (p ∧ ∼ q) ≡ p ∨ q

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Without using truth table prove that:

∼ [(p ∨ ∼ q) → (p ∧ ∼ q)] ≡ (p ∨ ∼ q) ∧ (∼ p ∨ q)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using rules in logic, prove the following:

p ↔ q ≡ ∼(p ∧ ∼q) ∧ ∼(q ∧ ∼p)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using rules in logic, prove the following:

∼p ∧ q ≡ (p ∨ q) ∧ ∼p

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using rules in logic, prove the following:

∼ (p ∨ q) ∨ (∼p ∧ q) ≡ ∼p

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using the rules in logic, write the negation of the following:

(p ∨ q) ∧ (q ∨ ∼r)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using the rules in logic, write the negation of the following:

p ∧ (q ∨ r)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using the rules in logic, write the negation of the following:

(p → q) ∧ r

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using the rules in logic, write the negation of the following:

(∼p ∧ q) ∨ (p ∧ ∼q)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Suppose `bar"a" = bar"0"`:

If `bar"a".bar"b" = bar"a".bar"c"`, then is `bar"b" = bar"c"` ?

[5] Vectors
Chapter: [5] Vectors
Concept: undefined >> undefined

Suppose `bar"a" = bar"0"`:

If `bar"a" xx bar"b" = bar"a" xx bar"c"`, then is `bar"b" = bar"c"` ?

[5] Vectors
Chapter: [5] Vectors
Concept: undefined >> undefined

Suppose `bar"a" = bar"0"`:

If `bar"a".bar"b" = bar"a".bar"c" and bar"a" xx bar"b" = bar"a" xx bar"c"`,  then is `bar"b" = bar"c"`?

[5] Vectors
Chapter: [5] Vectors
Concept: undefined >> undefined

A(2, 3), B(−1, 5), C(−1, 1) and D(−7, 5) are four points in the Cartesian plane, Check if, `bar("CD")` is parallel to `bar("AB")`

[5] Vectors
Chapter: [5] Vectors
Concept: undefined >> undefined

The non zero vectors `bar("a")` and `bar("b")` are not collinear find the value of `lambda` and `mu`: if `bar("a") + 3bar("b") = 2lambdabar("a") - mubar("b")`

[5] Vectors
Chapter: [5] Vectors
Concept: undefined >> undefined

If `bar("a") = 4hat"i" + 3hat"k"` and `bar("b") = -2hat"i" + hat"j" + 5hat"k"`, then find `2bar("a") + 5bar("b")`

[5] Vectors
Chapter: [5] Vectors
Concept: undefined >> undefined
< prev  1741 to 1760 of 1876  next > 
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