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HSC Arts (English Medium) 12th Standard Board Exam - Maharashtra State Board Question Bank Solutions

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Evaluate: `int_0^(pi/4) sec^4x  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^(pi/2) 1/(5 + 4cos x)  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

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Evaluate: `int_0^(pi/2) cos x/((1 + sinx)(2 + sinx))  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_(-1)^1 1/("a"^2"e"^x + "b"^2"e"^(-x))  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^"a" 1/(x + sqrt("a"^2 - x^2))  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^3 x^2 (3 - x)^(5/2)  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^1 "t"^2 sqrt(1 - "t")  "dt"`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^(1/2) 1/((1 - 2x^2) sqrt(1 - x^2))  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^(pi/4)  (sec^2x)/(3tan^2x + 4tan x + 1)  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_(1/sqrt(2))^1  (("e"^(cos^-1x))(sin^-1x))/sqrt(1 - x^2)  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^1 (log(x + 1))/(x^2 + 1)  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^pi x*sinx*cos^2x* "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_(-1)^1 (1 + x^2)/(9 - x^2)  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^1 (1/(1 + x^2)) sin^-1 ((2x)/(1 + x^2))  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^(pi/4)  (cos2x)/(1 + cos 2x + sin 2x)  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^(pi/4) log(1 + tanx)  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^pi 1/(3 + 2sinx + cosx)  "d"x`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

Evaluate: `int_0^(π/4) sec^4 x  dx`

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined

If u and v ore differentiable functions of x. then prove that:

`int uv  dx = u intv  dx - int [(du)/(d) intv  dx]dx`

Hence evaluate `intlog x  dx`

[10] Indefinite Integration
Chapter: [10] Indefinite Integration
Concept: undefined >> undefined

`int_0^(π/2) sin^6x cos^2x.dx` = ______.

[11] Definite Integration
Chapter: [11] Definite Integration
Concept: undefined >> undefined
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