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Solve the following equation for x, y ∈ R:
(4 – 5i) x + (2 + 3i) y = 10 – 7i
Concept: undefined >> undefined
Solve the following equation for x, y ∈ R:
(1 – 3i) x + (2 + 5i) y = 7 + i
Concept: undefined >> undefined
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Solve the following equation for x, y ∈ R:
`(x + "i"y)/(2 + 3"i")` = 7 – i
Concept: undefined >> undefined
Solve the following equation for x, y ∈ R:
(x + iy)(5 + 6i) = 2 + 3i
Concept: undefined >> undefined
Solve the following equation for x, y ∈ R:
2x + i9 y (2 + i) = x i7 + 10 i16
Concept: undefined >> undefined
Verify whether the following sequence is H.P.:
`1/3, 1/5, 1/7, 1/9`, ...
Concept: undefined >> undefined
Verify whether the following sequence is H.P.:
`1/3, 1/6, 1/9, 1/12`, ...
Concept: undefined >> undefined
Verify whether the following sequence is H.P.:
`1/7, 1/9, 1/11, 1/13, 1/15`, ...
Concept: undefined >> undefined
Find the nth term and hence find the 8th term of the following H.P.s:
`1/2, 1/5, 1/8, 1/11`, ...
Concept: undefined >> undefined
Find the nth term and hence find the 8th term of the following H.P.s:
`1/4, 1/6, 1/8, 1/10`, ...
Concept: undefined >> undefined
Find the nth term and hence find the 8th term of the following H.P.s:
`1/5, 1/10, 1/15, 1/20`, ...
Concept: undefined >> undefined
Insert two numbers between `1/7 and 1/13` so that the resulting sequence is a H.P.
Concept: undefined >> undefined
By using determinant, show that the following points are collinear: P(5, 0), Q(10, –3), R(–5, 6)
Concept: undefined >> undefined
Evaluate the following: `lim_(x -> 0)[(9^x - 5^x)/(4^x - 1)]`
Concept: undefined >> undefined
Evaluate the following: `lim_(x -> 0)[(5^x + 3^x - 2^x - 1)/x]`
Concept: undefined >> undefined
Evaluate the following: `lim_(x -> 0)[(log(2 + x) - log( 2 - x))/x]`
Concept: undefined >> undefined
Evaluate the following: `lim_(x -> 0) [(3^x + 3^-x - 2)/x^2]`
Concept: undefined >> undefined
Evaluate the following: `lim_(x -> 0) [(3 + x)/(3 - x)]^(1/x)`
Concept: undefined >> undefined
Evaluate the following: `lim_(x -> 0)[(log(3 - x) - log(3 + x))/x]`
Concept: undefined >> undefined
Evaluate the following: `lim_(x -> 0) [("a"^(3x) - "b"^(2x))/(log 1 + 4x)]`
Concept: undefined >> undefined
