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HSC Arts (English Medium) 11th Standard - Maharashtra State Board Question Bank Solutions for Mathematics and Statistics

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Mathematics and Statistics
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Evaluate the following limit :

`lim_(y -> 1)[(2y - 2)/(root(3)(7 + y) - 2)]`

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

Evaluate the following limit :

`lim_(z -> "a")[((z + 2)^(3/2) - ("a" + 2)^(3/2))/(z - "a")]`

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

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Evaluate the following limit :

`lim_(x -> 7) [(x^3 - 343)/(sqrt(x) - sqrt(7))]`

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

Evaluate the following limit :

`lim_(x -> 1) [(x + x^3 + x^5 + ... + x^(2"n" - 1) - "n")/(x - 1)]`

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

In the following example, given ∈ > 0, find a δ > 0 such that whenever, |x – a| < δ, we must have |f(x) – l| < ∈.

`lim_(x -> 2)(2x + 3)` = 7

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

In the following example, given ∈ > 0, find a δ > 0 such that whenever, |x – a| < δ, we must have |f(x) – l| < ∈.

`lim_(x -> -3) (3x + 2)` = – 7

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

In the following example, given ∈ > 0, find a δ > 0 such that whenever, |x – a| < δ, we must have |f(x) – l| < ∈.

`lim_(x -> 2) (x^2 - 1)` = 3

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

In the following example, given ∈ > 0, find a δ > 0 such that whenever, |x – a| < δ, we must have |f(x) – l| < ∈.

`lim_(x -> 1) (x^2 + x + 1)` = 3

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

Evaluate the following :

`lim_(x -> 0)[x/(|x| + x^2)]`

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

Evaluate the following :

Find the limit of the function, if it exists, at x = 1

f(x) = `{(7 - 4x, "for", x < 1),(x^2 + 2, "for", x ≥ 1):}`

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

Evaluate the following :

Given that 7x ≤ f(x) ≤ 3x2 – 6 for all x. Determine the value of `lim_(x -> 3) "f"(x)`

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

Evaluate the following :

`lim_(x -> 0) [(sqrt(1 - cosx))/x]`

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

Evaluate the following :

`lim_(x -> 1) [(x + 3x^2 + 5x^3 + ... + (2"n" - 1)x^"n" - "n"^2)/(x - 1)]`

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

Evaluate the following :

`lim_(x -> 0) {1/x^12 [1 - cos(x^2/2) - cos(x^4/4) + cos(x^2/2) cos(x^4/4)]}`

[2.7] Limits
Chapter: [2.7] Limits
Concept: undefined >> undefined

Examine the continuity of f(x) = x3 + 2x2 − x − 2 at x = − 2

[2.8] Continuity
Chapter: [2.8] Continuity
Concept: undefined >> undefined

Examine the continuity of `"f"(x)  {:(= sin x",",  "for"  x ≤ pi/4), (= cos x",",  "for"  x > pi/4):}}  "at"  x = pi/4`

[2.8] Continuity
Chapter: [2.8] Continuity
Concept: undefined >> undefined

Examine the continuity of `f(x) = {:((x^2 - 9)/(x  - 3)",",  "for"  x ≠ 3),(=8",",  "for"  x = 3):}}` at x = 3.

[2.8] Continuity
Chapter: [2.8] Continuity
Concept: undefined >> undefined

Examine whether the function is continuous at the points indicated against them:

f(x)  `{:(= x^3 - 2x + 1",",  "if"  x ≤ 2),(= 3x - 2",",  "if"  x > 2):}}` at x = 2

[2.8] Continuity
Chapter: [2.8] Continuity
Concept: undefined >> undefined

Examine whether the function is continuous at the points indicated against them :

f(x) `{:( = (x^2 + 18x - 19)/(x - 1)",",  "for"  x ≠ 1),(= 20",",  "for"  x = 1):}}` at x = 1

[2.8] Continuity
Chapter: [2.8] Continuity
Concept: undefined >> undefined

Examine whether the function is continuous at the points indicated against them :

f(x) `{:(= x/(tan3x) + 2",",   "for"  x < 0),(= 7/3",",  "for"  x ≥ 0):}}  "at"  x = 0`

[2.8] Continuity
Chapter: [2.8] Continuity
Concept: undefined >> undefined
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