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Science (English Medium) Class 12 - CBSE Question Bank Solutions for Mathematics

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A shopkeeper has 3 varieties of pens 'A', 'B' and 'C'. Meenu purchased 1 pen of each variety for a total of Rs 21. Jeevan purchased 4 pens of 'A' variety 3 pens of 'B' variety and 2 pens of 'C' variety for Rs 60. While Shikha purchased 6 pens of 'A' variety, 2 pens of 'B' variety and 3 pens of 'C' variety for Rs 70. Using matrix method, find cost of each variety of pen.

 
[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

2x − y + z = 0
3x + 2y − z = 0
x + 4y + 3z = 0

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

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2x − y + 2z = 0
5x + 3y − z = 0
x + 5y − 5z = 0

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

3x − y + 2z = 0
4x + 3y + 3z = 0
5x + 7y + 4z = 0

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

x + y − 6z = 0
x − y + 2z = 0
−3x + y + 2z = 0

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

x + y + z = 0
x − y − 5z = 0
x + 2y + 4z = 0

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

x + y − z = 0
x − 2y + z = 0
3x + 6y − 5z = 0

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

3x + y − 2z = 0
x + y + z = 0
x − 2y + z = 0

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

2x + 3y − z = 0
x − y − 2z = 0
3x + y + 3z = 0

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined
If \[\begin{bmatrix}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{bmatrix}\begin{bmatrix}x \\ y \\ z\end{bmatrix} = \begin{bmatrix}1 \\ - 1 \\ 0\end{bmatrix}\], find x, y and z.
[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

If \[\begin{bmatrix}1 & 0 & 0 \\ 0 & - 1 & 0 \\ 0 & 0 & - 1\end{bmatrix}\begin{bmatrix}x \\ y \\ z\end{bmatrix} = \begin{bmatrix}1 \\ 0 \\ 1\end{bmatrix}\], find x, y and z.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

If \[\begin{bmatrix}1 & 0 & 0 \\ 0 & y & 0 \\ 0 & 0 & 1\end{bmatrix}\begin{bmatrix}x \\ - 1 \\ z\end{bmatrix} = \begin{bmatrix}1 \\ 0 \\ 1\end{bmatrix}\] , find x, y and z.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Solve the following for x and y: \[\begin{bmatrix}3 & - 4 \\ 9 & 2\end{bmatrix}\binom{x}{y} = \binom{10}{ 2}\]

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined
If \[\begin{bmatrix}1 & 0 & 0 \\ 0 & 0 & 1 \\ 0 & 1 & 0\end{bmatrix}\begin{bmatrix}x \\ y \\ z\end{bmatrix} = \begin{bmatrix}2 \\ - 1 \\ 3\end{bmatrix}\], find x, y, z.
[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined
If \[A = \begin{bmatrix}2 & 4 \\ 4 & 3\end{bmatrix}, X = \binom{n}{1}, B = \binom{ 8}{11}\]  and AX = B, then find n.
[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

The system of equation x + y + z = 2, 3x − y + 2z = 6 and 3x + y + z = −18 has

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

The number of solutions of the system of equations
2x + y − z = 7
x − 3y + 2z = 1
x + 4y − 3z = 5
is

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Let \[X = \begin{bmatrix}x_1 \\ x_2 \\ x_3\end{bmatrix}, A = \begin{bmatrix}1 & - 1 & 2 \\ 2 & 0 & 1 \\ 3 & 2 & 1\end{bmatrix}\text{ and }B = \begin{bmatrix}3 \\ 1 \\ 4\end{bmatrix}\] . If AX = B, then X is equal to

 

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

The number of solutions of the system of equations:
2x + y − z = 7
x − 3y + 2z = 1
x + 4y − 3z = 5

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

The system of linear equations:
x + y + z = 2
2x + y − z = 3
3x + 2y + kz = 4 has a unique solution if

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined
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