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Commerce (English Medium) Class 12 - CBSE Question Bank Solutions for Mathematics

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Mathematics
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Find  fog (2) and gof (1) when : f : R → R ; f(x) = x2 + 8 and g : R → Rg(x) = 3x3 + 1.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let R+ be the set of all non-negative real numbers. If f : R+ → R+ and g : R+ → R+ are defined as `f(x)=x^2` and `g(x)=+sqrtx` , find fog and gof. Are they equal functions ?

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

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Let f : R → R and g : R → R be defined by f(x) = x2 and g(x) = x + 1. Show that fog ≠ gof.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let f : R → R and g : R → R be defined by f(x) = + 1 and (x) = x − 1. Show that fog = gof = IR.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Verify associativity for the following three mappings : f : N → Z0 (the set of non-zero integers), g : Z0 → Q and h : Q → R given by f(x) = 2xg(x) = 1/x and h(x) = ex.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Consider f : N → Ng : N → N and h : N → R defined as f(x) = 2xg(y) = 3y + 4 and h(z) = sin z for all xyz ∈ N. Show that ho (gof) = (hogof.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Give examples of two functions f : N → N and g : N → N, such that gof is onto but f is not onto.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Give examples of two functions f : N → Z and g : Z → Z, such that gof is injective but gis not injective.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

If f : A → B and g : B → C are one-one functions, show that gof is a one-one function.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

If f : A → B and g : B → C are onto functions, show that gof is a onto function.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

 Find fog and gof  if  : f (x) = ex g(x) = loge x .

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find fog and gof  if : f (x) = x2 g(x) = cos x .

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find fog and gof  if : f (x) = |x|, g (x) = sin x .

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find fog and gof  if : f (x) = x+1, g(x) = `e^x`

.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find fog and gof  if : f(x) = sin−1 x, g(x) = x2

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find fog and gof  if : f (x) = x+1, g (x) = sin x .

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find fog and gof  if : f(x)= x + 1, g (x) = 2x + 3 .

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find fog and gof  if : f(x) = c, c ∈ R, g(x) = sin `x^2`

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Find fog and gof  if : f(x) = `x^2` + 2 , g (x) = 1 − `1/ (1-x)`.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let f(x) = x2 + x + 1 and g(x) = sin x. Show that fog ≠ gof.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined
< prev  1881 to 1900 of 8364  next > 
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