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Question
Xenon crystallizes in fee lattice and the edge length of unit cell is 620 pm. What is the radius of Xe atom?
Options
536.9 pm
438.5 pm
265.5 pm
219.2 pm
MCQ
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Solution
219.2 pm
Explanation:
a = 620 pm
For fee unit cell, r = `"a"/(2sqrt2)`
`therefore "r" = 620/(2 xx 1.414)` = 219.2 pm
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Crystal Structure
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