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Question
`intx^2/sqrt(1 - x^6)dx` is equal to ______
Options
`sin^-1 x^2 + c`
`2/3 sin^-1x^3 + c`
`1/3sin^-1 x^3 + c`
`1/2sin^-1x^2 + c`
MCQ
Fill in the Blanks
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Solution
`intx^2/sqrt(1 - x^6)dx` is equal to `underline(1/3sin^-1 x^3 + c)`.
Explanation:
Let I = `intx^2/sqrt(1 - x^6)dx`
= `intx^2/sqrt(1 - (x^3)^2)dx`
Put x3 = t ⇒ 3x2 dx = dt
∴ I = `1/3int1/sqrt(1 - t^2)dt`
= `1/3sin^-1t + c`
∴ I = `1/3sin^-1(x^3) + c`
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Some Special Integrals
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