Question

Write the relative rate expressions for the following chemical reaction:

\[\ce{4NH3_{(g)} + 5O2_{(g)} -> 4NO_{(g)} + 6H2O_{(g)}}\]

Answer 1

For the reaction \[\ce{4NH3_{(g)} + 5O2_{(g)} -> 4NO_{(g)} + 6H2O_{(g)}}\]

Relative rate expressions are written by dividing the rate of change of concentration of each species by its stoichiometric coefficient.

Rate = \[\ce{\frac{1}{4} \frac{d[NH_3]}{dt}}\]

Rate = \[\ce{\frac{1}{5} \frac{d[O_2]}{dt}}\]

Rate = \[\ce{\frac{1}{4} \frac{d[NO_2]}{dt}}\]

Rate = \[\ce{\frac{1}{6} \frac{d[H_2O]}{dt}}\]