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Question
Write the oxidation state of the elements of first transition series. What conclusion may be drawn from these oxidation states?
Very Long Answer
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Solution
| Atomic number | Element | Symbol | Electronic configuration |
| 21 | Scandium | Sc | 1s2 2s2 p6 3s2 p6 d1 4s2 |
| 22 | Titanium | Ti | 1s2 2s2 p6 3s2 p6 d2 4s2 |
| 23 | Vanadium | V | 1s2 2s2 p6 3s2 p6 d3 4s2 |
| 24 | Chromium | Cr | 1s2 2s2 p6 3s2 p6 d5 4s1 |
| 25 | Manganese | Mn | 1s2 2s2 p6 3s2 p6 d5 4s2 |
| 26 | Iron | Fe | 1s2 2s2 p6 3s2 p6 d6 4s2 |
| 27 | Cobalt | Co | 1s2 2s2 p6 3s2 p6 d7 4s2 |
| 28 | Nickel | Ni | 1s2 2s2 p6 3s2 p6 d8 4s2 |
| 29 | Copper | Cu | 1s2 2s2 p6 3s2 p6 d10 4s1 |
| 30 | Zinc | Zn | 1s2 2s2 p6 3s2 p6 d10 4s2 |
The ten elements in this series, which range from Sc (At. No. = 21) to Zn (At. No. = 30), correspond to the filling of the 3d-subshell. The periodic table's fourth period includes these elements.
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