Question

Write the ionic equations to represent the oxidising nature of KMnO₄ in alkaline solution.

Answer 1

In the presence of an alkali, purple potassium permanganate transforms to green potassium manganate.

\[\ce{\underset{(purple)}{\underset{Pot. permanganate}{2KMnO4}} + 2KOH -> \underset{(green)}{\underset{Pot. manganate}{2K2MnO4}} + H2O + O}\]

Potassium manganate is reduced to MnO₂ in the presence of a reducing agent.

\[\ce{K2MnO4 + H2O -> MnO2 + 2KOH + O}\]

Therefore, the complete reaction is

\[\ce{2KMnO4 + H2O -> 2MnO2 + 2KOH + 3O}\]

In alkaline solutions, the process includes reducing MnO₄ ions to MnO₂. In ionic form, it is written as follows.

\[\ce{MnO^-_4 + e- -> MnO^{2-}_4}\]

\[\ce{MnO^{2-}_4 + 2H2O + 2e- -> MnO2 + 4OH-}\]

\[\ce{\overline{\text{MnO}^-_4 + 2\text{H}_2\text{O} + 3\text{e}^- \leftarrow \text{MnO}_2 + 4\text{OH}^-}}\]