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Question
Write the observation and name of the product for the following
(i) When ethene is passed in bromine solution in CCl4.
(ii) When Baeyer's reagent reacts with ethene.
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Solution
(i) When ethene is passed in bromine solution in CCI4, the orange colour of bromine disappears due to formation of colourless ethylene bromide.
\[\ce{CH2 = CH2 + Br2 -> CH2Br - CH2Br}\]
(ii) When Baeyer's reagent reacts with ethene, colour of potassium permanganate gets discharged in this reaction.
\[\ce{CH2 = Ch2 + H2O + O ->[25°C-30°C][KMnO] Ch2OH - CH2OH}\]
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\[\begin{array}{cc}
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