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Question
Write nuclear reaction of nuclear fusion.
Short Answer
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Solution
\[\ce{\underset{(Deuterium)}{^2_1H}+ \underset{(Deuterium)}{^2_1H}-> \underset{(Helium isotope)}{^3_2He}+ \underset{(Neutron)}{^0_1n}+ 3.3 MeV}\]
\[\ce{\underset{(Helium isotope)}{^3_2He}+ \underset{(Deuterium)}{^2_1H} -> \underset{(Helium)}{^4_2He}+ \underset{(Proton)}{^1_1H} + 18.3 MeV}\]
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Chapter 12: Radioactivity - EXERCISE - 12(B) [Page 306]
