Question

Write the first three terms of the A.P. whose common difference is ‒3 and first term is 4.

Answer 1

a = 4, d = –3
Hence,
t₁ = 4
t₂ = t₁ + d = 4 + (–3) = 4 – 3 = 1
t₃ = t₂ + d = 1 + (–3) = 1 – 3 = –2
Thus, the first three terms of the A.P. are 4, 1 and –2.