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Question
Write the first three terms of the A.P. whose common difference is ‒3 and first term is 4.
Solution
a = 4, d = –3
Hence,
t1 = 4
t2 = t1 + d = 4 + (–3) = 4 – 3 = 1
t3 = t2 + d = 1 + (–3) = 1 – 3 = –2
Thus, the first three terms of the A.P. are 4, 1 and –2.
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