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Write the Direction Cosines of the Vector → R = 6 ^ I − 2 ^ J + 3 ^ K . - Mathematics

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Question

Write the direction cosines of the vector \[\overrightarrow{r} = 6 \hat{i} - 2 \hat{j} + 3 \hat{k} .\]

Sum
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Solution

Given: \[\overrightarrow{r} = 6 \hat{i} - 2 \hat{j} + 3 \hat{k}\]
Then, direction cosines of \[\stackrel\frown{r}\] are \[\frac{6}{\sqrt{6^2 + \left( - 2 \right)^2 + 3^2}} , \frac{- 2}{\sqrt{6^2 + \left( - 2 \right)^2 + 3^2}} , \frac{3}{\sqrt{6^2 + \left( - 2 \right)^2 + 3^2}}\]
or,
\[\frac{6}{7}, \frac{- 2}{7}, \frac{3}{7}\]

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Chapter 23: Algebra of Vectors - Very Short Answers [Page 76]

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RD Sharma Mathematics [English] Class 12
Chapter 23 Algebra of Vectors
Very Short Answers | Q 22 | Page 76
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