Advertisements
Advertisements
Question
In the given figure; ∠B = 90°, ∠ADB = 30°, ∠ACB = 45° and AB = 24 m. Find the length of CD.
Advertisements
Solution
In right ΔABC,
tan45° = `"AB"/"BC"`
⇒ 1 = `(24)/"BC"`
⇒ BC = 24m.
In right ΔABD,
tan 30° = `"AB"/"BD"`
⇒ `(1)/sqrt(3) = (24)/"BD"`
⇒ BD = `24sqrt(3)"m"`
Now,
CD = BD - BC
= `24sqrt(3) - 24`
= `24(sqrt(3) - 1)"m"`.
APPEARS IN
RELATED QUESTIONS
If 2 cos (A + B) = 2 sin (A - B) = 1;
find the values of A and B.
Solve for x : 3 tan2 (2x - 20°) = 1
Find the value of 'A', if `sqrt(3)cot"A"` = 1
If θ = 30°, verify that: sin 3θ = 4sinθ . sin(60° - θ) sin(60° + θ)
Evaluate the following: `((1 - cosθ)(1 + cosθ))/((1 - sinθ)(1 + sinθ)` if θ = 30°
If `sqrt(3)` sec 2θ = 2 and θ< 90°, find the value of
cos2 (30° + θ) + sin2 (45° - θ)
Find the value 'x', if:
Evaluate the following: `(sec34°)/("cosec"56°)`
Evaluate the following: sin31° - cos59°
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: sin53° + sec66° - sin50°
