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Write a balanced chemical equation for the following. A 50% solution of sulphuric acid is subjected to electrolyte oxidation and the product is hydrolysed. - Chemistry

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Question

Write a balanced chemical equation for the following.

A 50% solution of sulphuric acid is subjected to electrolyte oxidation and the product is hydrolysed.

One Line Answer
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Solution

  • Electrolytic oxidation:
    At anode: 
    \[\ce{2HSO4^{-}->[Electrolysis]\underset{\text{Peroxydisulphuric acid}}{H2S2O8} + 2e^-}\]
  • Hydrolysis:

    \[\ce{\underset{\text{Peroxydisulphuric acid}}{HO - SO2 - O - O} - SO2 - OH + 2H2O->2H2SO4 + \underset{\text{Hydrogen peroxide}}{H2O2}}\]
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Alkali Metals and Alkaline Earth Metals
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Chapter 8: Elements of Group 1 and 2 - Exercises [Page 122]

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Balbharati Chemistry [English] Standard 11 Maharashtra State Board
Chapter 8 Elements of Group 1 and 2
Exercises | Q 2. (B) | Page 122

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