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Maharashtra State BoardSSC (English Medium) 10th Standard

Wo Roots of Quadratic Equations Are Given ; Frame the Equation. 1 − 3 √ 5 and 1 + 3 √ 5 - Algebra

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Question

Two roots of quadratic equation is given ; frame the equation.

\[1 - 3\sqrt{5} \text{ and } 1 + 3\sqrt{5}\] 

Sum
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Solution

\[1 - 3\sqrt{5} \text{ and } 1 + 3\sqrt{5}\]

Sum of roots = \[1 - 3\sqrt{5} + 1 + 3\sqrt{5} = 2\]

Product of roots = \[\left( 1 - 3\sqrt{5} \right)\left( 1 + 3\sqrt{5} \right) = 1 - 45 = - 44\]

The general form of the quadratic equation is \[x^2 - \left( \text{ Sum of roots } \right)x + \text{ product of roots } = 0\]

So, the quadratic equation will be  \[x^2 - 2x - 44 = 0\]

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Chapter 2: Quadratic Equations - Problem Set 2 [Page 54]

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Balbharati Algebra (Mathematics 1) [English] Standard 10 Maharashtra State Board
Chapter 2 Quadratic Equations
Problem Set 2 | Q 5.2 | Page 54
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