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Without using tables verify that cos 60° = cos^2 30° – sin^2 30°. - Mathematics

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Question

Without using tables verify that cos 60° = cos2 30° – sin2 30°.

Sum
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Solution

Given: cos 60° = cos2 30° – sin2 30°.

Step-wise calculation:

1. Use the double-angle identity cos (2θ) = cos2θ – sin2θ.

2. Put θ = 30°:

cos 60° = cos2 30° – sin2 30°   ...(This is the identity specialized to 30°)

3. Evaluate the basic values:

`cos 30^circ = sqrt(3)/2` and `sin 30^circ = 1/2`

4. Compute:

cos2 30° – sin2 30°

= `(sqrt(3)/2)^2 - (1/2)^2`

= `3/4 - 1/4`

= `1/2`

5. Note `cos 60^circ = 1/2`, matching the result.

`cos 60^circ = 1/2 = cos^2 30^circ - sin^2 30^circ`, so the identity is verified.

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Chapter 18: Trigonometric Ratios of Some Standard Angles and Complementary Angles - Exercise 18A [Page 373]

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Nootan Mathematics [English] Class 9 ICSE
Chapter 18 Trigonometric Ratios of Some Standard Angles and Complementary Angles
Exercise 18A | Q 15. | Page 373
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