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Why do the d-block elements exhibit a larger number of oxidation states than the f-block elements? - Chemistry (Theory)

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Why do the d-block elements exhibit a larger number of oxidation states than the f-block elements?

Explain the following:

d-block elements exhibit more oxidation states than f-block elements.

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Solution

  1. d-block elements have (n − 1)d and ns orbitals close in energy, allowing variable involvement of these electrons in bonding.
  2. They can lose different numbers of (n − 1)d and ns electrons, leading to multiple oxidation states.
  3. In contrast, f-block elements have electrons in the more inner 4f or 5f orbitals, which are more deeply buried and less available for bonding.
  4. f-electrons are well shielded and have similar energy, limiting the range of stable oxidation states.
  5. Actinoids (f-block) show more oxidation states than lanthanoids due to involvement of 5f and 6d orbitals, but still fewer than d-block.

Hence, the accessibility and energy proximity of d and s electrons in d-block elements result in a larger variety of oxidation states compared to f-block elements.

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Chapter 8: d-and ƒ-Block Elements - REVIEW EXERCISES [Page 477]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 8 d-and ƒ-Block Elements
REVIEW EXERCISES | Q 8.21 (a) | Page 477
Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 8 d-and ƒ-Block Elements
REVIEW EXERCISES | Q 8.31 (ii) | Page 477
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