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Why are organic compounds studies as a separate branch of chemistry?

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Question

Why are organic compounds studies as a separate branch of chemistry?

Short Answer
Very Short Answer
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Solution 1

Due to the unique nature of carbon atoms, it gives rise to the formation of a large number of compounds. Thus, the process demands a separate branch of chemistry.

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Solution 2

Organic compounds follow the same fundamental chemistry laws as inorganic compounds, but have unique characteristics such as large numbers, tetravalency of carbon, composition, linkage, melting and boiling points, stability, combustibility, origin, isomerism, and reaction nature, necessitating separate study.

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Chapter 12: Organic Chemistry - Intext Questions [Page 187]

APPEARS IN

S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 12 Organic Chemistry
Intext Questions | Q 7. | Page 187

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\phantom{......}\ce{H}\phantom{..}\ce{H}\phantom{..}\ce{H}\phantom{........}\\
\phantom{}|\phantom{...}|\phantom{...}|\phantom{..}\\
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\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C = C - C - H}\\
|\phantom{.............}|\\
\ce{H}\phantom{............}\ce{H}
\end{array}\]

B

\[\begin{array}{cc}
\phantom{.......}\ce{H}\phantom{.....}\ce{O}\\
\phantom{.......}|\phantom{.....}//\\
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\phantom{......}|\phantom{.....}\backslash\\
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C

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
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|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]

D

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{O}\\
\phantom{.......}\backslash\\
\phantom{.........}\ce{H}
\end{array}\]

E

\[\begin{array}{cc}
\ce{H}\\
|\\
\ce{H - C - H}\\
\ce{H}\phantom{....}\phantom{....}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}
\end{array}\]

F

\[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{C = C}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}
\end{array}\]

  1. Identify two of the compounds that are members of the same homologous series but are not isomers.
  2. Which two compounds are isomers of each other?
  3. F can be prepared from D. Give a chemical equation for the reaction.

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