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Which of the following solutions will have a lower vapour pressure and why? (i)A 5% solution of cane sugar (C12H22O11) (ii) A 5% solution of urea (NH2CONH2) (Relative atomic masses: H = 1, C = 12, - Chemistry (Theory)

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Question

Which of the following solutions will have a lower vapour pressure and why? 

  1. A 5% solution of cane sugar (C12H22O11)
  2. A 5% solution of urea (NH2CONH2)

(Relative atomic masses: H = 1, C = 12, O = 16, N = 14)

Long Answer
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Solution

The 5% urea solution will have a lower vapour pressure than the 5% cane sugar solution.

Reason:
Vapour pressure lowering is a colligative property and depends on the number of solute particles (moles), not their type.

  1. Molar mass of cane sugar (C12H22O11) = 342 g/mol → moles in 5 g = `5/342` = 0.0146 mol.
  2. Molar mass of urea (NH2CONH2) = 60 g/mol → moles in 5 g = `5/60` = 0.0833 mol.

Since urea gives more moles in the same mass, it causes greater vapour pressure lowering.

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Chapter 2: Solutions - QUESTIONS FROM ISC EXAMINATION PAPERS [Page 130]

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Nootan Chemistry Part 1 and 2 [English] Class 12 ISC
Chapter 2 Solutions
QUESTIONS FROM ISC EXAMINATION PAPERS | Q 7. (c) | Page 130
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