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Question
Which isomer of C4H9Cl will have the lowest boiling point and why?
Short Answer
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Solution
The isomer of C4H9Cl with the lowest boiling point is 2-chloro-2-methylpropane (also known as tert-butyl chloride) because its highly branched, compact structure minimizes the surface area available for intermolecular forces, particularly Van der Waals forces, requiring less energy to separate the molecules during boiling.
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