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Question
When the concentration of a reactant of first order reaction is doubled, the rate becomes ______ times, but for ______ order reaction, the rate remains same.
Fill in the Blanks
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Solution
When the concentration of a reactant of first order reaction is doubled, the rate becomes two times, but for zero order reaction, the rate remains same.
Explanation:
First-order reaction:
Rate = k[A]1
⇒ Rate ∝ [A]
So, doubling [A] doubles the rate.
Zero-order reaction:
Rate = k[A]0 = k
The rate is independent of the concentration of reactant.
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