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Question
When electricity is passed through a solution of AlCl3, 13.5 g of Al is discharged, the amount of charge passed is ______.
Options
1.5 F
0.5 F
1.0 F
2.0 F
MCQ
Fill in the Blanks
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Solution
When electricity is passed through a solution of AlCl3, 13.5 g of Al is discharged, the amount of charge passed is 1.5 F.
Explanation:
Aluminium is deposited from aluminium chloride (AlCl3) according to the half-cell reaction:
\[\ce{Al^3+ + 3e- -> Al}\]
Equivalent mass of Al = `27/3` = 9
Mass deposited = 13.5 g
Now using Faraday’s law,
Charge = `"Mass"/"Equivalent mass"`
= `13.5/9`
= 1.5 F
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