Question

When aqueous solutions of potassium iodide and lead nitrate are mixed an insoluble substance separates out. The chemical equation for the reaction involved is: 

Options

• \[\ce{KI + PbNO_3 ->PbI + KNO3}\]

• \[\ce{2KI + Pb(NO_3)2 ->PbI2 + 2KNO3}\]

• \[\ce{KI + Pb(NO_3)2 ->PbI + KNO3}\]

• \[\ce{KI + Pb(NO_3)2 ->PbI2 + 2KNO3}\]

Answer 1

\[\ce{2KI + Pb(NO_3)2 ->PbI2 + 2KNO3}\]

Explanation:

It will produce a yellow precipitate of lead iodide (PbI₂).