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Question
When aqueous solutions of potassium iodide and lead nitrate are mixed an insoluble substance separates out. The chemical equation for the reaction involved is:
Options
\[\ce{KI + PbNO_3 ->PbI + KNO3}\]
\[\ce{2KI + Pb(NO_3)2 ->PbI2 + 2KNO3}\]
\[\ce{KI + Pb(NO_3)2 ->PbI + KNO3}\]
\[\ce{KI + Pb(NO_3)2 ->PbI2 + 2KNO3}\]
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Solution
\[\ce{2KI + Pb(NO_3)2 ->PbI2 + 2KNO3}\]
Explanation:
It will produce a yellow precipitate of lead iodide (PbI2).
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