Question

When an alternating voltage E = E₀ sin ωt is applied to a circuit, a current `I = I_0 sin(omegat + pi/2)` flows through it The average power dissipated in the circuit is ______.

Options

• E_rms . I_rms

• E₀I₀

• `(E_0I_0)/sqrt2`

• Zero

Answer 1

When an alternating voltage E = E₀ sin ωt is applied to a circuit, a current `I = I_0 sin(omegat + pi/2)` flows through it The average power dissipated in the circuit is zero.

Explanation:

Power = V_rms × I_rms × cosΦ

Here `phi = pi/2`

So, Power = 0