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What will be the cartesian equation of the following plane. r→⋅(i^+j^-k^) = 2 -

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Question

What will be the cartesian equation of the following plane. `vecr * (hati + hatj - hatk)` = 2

Options

  • `2x + 3y - 4x` = 1

  • `x + y - z` = 2

  • `x + 3y - z = 1/2`

  • `x + 2y - 3z` = 1

MCQ

Solution

`x + y - z` = 2

Explanation:

`vecr = xhati + yhatj + zhatk`

`vecr = (hati + hatj + hatk)` = 2

⇒ `(xhati + yhati + zhatk) * (hati + hatj - hatk)` = 2

⇒ `(x)(1) + (y)(1) + (z)(-1)` = 2

⇒ `x + y - z` = 2

Which is the required cartesian equation.

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