A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at STP)NH4NO3 → N2O + 2H2OWhat volume of dinitrogen oxide is produced at the same time as 8.96 L of steam?

NH4NO3 → N2O + 2H2OFrom the equation:1 mole of NH4NO3 yields 2 mole of H2O.So, 44.8L of steam = 22.4L of N2O at STP.8.96L of Steam = 22.4 x 8.96/44.8 = 4.48L of N2O at STP.

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What Volume of Dinitrogen Oxide is Produced at the Same Time as 8.96 L of Steam?

Question

A sample of ammonium nitrate when heated yields 8.96 litres of steam (measured at STP)
NH₄NO₃ → N₂O + 2H₂O
What volume of dinitrogen oxide is produced at the same time as 8.96 L of steam?

Sum

Solution

NH₄NO₃ → N₂O + 2H₂O
From the equation:
1 mole of NH₄NO₃ yields 2 mole of H₂O.
So, 44.8L of steam = 22.4L of N₂O at STP.
8.96L of Steam = 22.4 x 8.96/44.8 = 4.48L of N₂O at STP.