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Question
What should be added to 4c(– a + b + c) to obtain 3a(a + b + c) – 2b(a – b + c)?
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Solution
Let x be added to the given expression
4c(– a + b + c) to obtain 3a(a + b + c) – 2b(a – b + c)
i.e. x + 4c(– a + b + c) = 3a(a + b + c) – 2b(a – b + c)
⇒ x = 3a(a + b + c) – 2b(a – b + c) – 4c(– a + b + c)
= 3a2 + 3ab + 3ac – 2ba + 2b2 – 2bc + 4ca – 4cb – 4c2
⇒ x = 3a2 + ab + 7ac + 2b2 – 6bc – 4c2 ...[Adding the like terms]
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