Question

What is the probability that an ordinary year has 53 Sundays?

 

Answer 1

There are 365 days, i.e. 52 weeks and one day
This one day can be any of the seven days of the week.
∴ P (Sunday) = \[\frac{1}{7}\]

We know that 52 weeks will have 52 Sundays.
Hence, required probability = P (an ordinary year with 53 Sundays) = \[\frac{1}{7}\]