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Question
what is the value of `cos^-1 (cos (13pi)/6)`
Options
`pi/2`
`pi/4`
`pi/6`
`pi/8`
MCQ
Solution
`pi/6`
Explanation:
`cos^-1 (cos (13pi)/6)`
`cos^-1 [cos(2pi + pi/6)]`
`cos^-1 [cos(pi/6)] = pi/6`
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