Question

What is the potential of a half-cell consisting of zinc electrode in 0.01 M ZnSO₄ solution at 25°C (E⁰ = −0.763 V)?

Options

• −0.8222 V

• 8.222 V

• −0.5282 V

• 9.232 V

Answer 1

−0.8222 V

Explanation:

Using the Nernst equation,

`"E"_"electrode" = "E"^0 - 0.0592/2 log  1/(["Zn"^(2+)])`

= `-0.763 - 0.0592/2 log  1/0.01`

= −0.763 − 0.0592

= −0.8222 V