Question

What is the molar mass of the amine formed when acetamide undergoes Hofmann bromamide degradation?

Options

• 31 g/mol

• 35 g/mol

• 45 g/mol

• 59 g/mol

Answer 1

31 g/mol

Explanation:

\[\begin{array}{cc}
\ce{O}\phantom{............................................................}\\
||\phantom{............................................................}\\
\ce{\underset{Acetamide}{CH3 - C - NH2} + Br2 + 4KOH_{(aq)} ->[\Delta] \underset{Methylamine}{CH3 - NH2} + 2KBr + K2CO3 + 2H2O}
\end{array}\]

Molar mass of methylamine = (1 × 12 + 1 × 14 + 5 × 1) = 31 g/mol