Question

What happens when 1-chloropropane is heated at 573 K?

Answer 1

When 1-chloropropane (CH₃CH₂CH₂Cl) is heated at 573 K, it undergoes dehydrohalogenation in a bimolecular elimination reaction (E2), leading to the formation of propene (CH₂ = CHC₃).

\[\ce{\underset{1-chloropropane}{CH3CH2CH2Cl} ->[573K][] \underset{propene }{CH2 = CHCH3} + HCl}\]