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Weight (kg) 40 – 45 45 – 50 50 –55 55 – 60 60 –65 65 –70 70 – 75 75 – 80 No. of person 4 15 20 30 20 10 8 4 For above data, find all quartiles and number of persons weighing between 57 kg and 72 kg. - Mathematics and Statistics

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Question

Weight (kg) 40 – 45 45 – 50 50 – 55 55 – 60 60 – 65 65 –70 70 – 75 75 – 80
No. of person 4 15 20 30 20 10 8 4

For above data, find all quartiles and number of persons weighing between 57 kg and 72.

Sum
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Solution

We construct the less than cumulative frequency table as given below:

Weight (kg) No. of persons
(f)
Less than cumulative frequency
(c.f.)
40 – 45 4 4
45 – 50 15 19
50 – 55 20 39 ← Q1
55 – 60 30 69 ← Q2, Px
60 – 65 20 89 ← Q3
65 – 70 10 99
70 – 75 8 107 ← Py
75 – 80 4 111
Total N = 111  

Here, N = 111

Q1 class = class containing `("N"/4)^"th"` observation

∴ `"N"/4 = 111/4` = 27.75
Cumulative frequency which is just greater than (or equal) to 27.75 is 39.
∴ Q1 lies in the class 50 – 55.
∴ L = 50, h = 5, f = 20, c.f. = 19

∴ Q1 = `L + h/f(N/4 - c.f.)`

= `50 + 5/20(27.75- 19)`

= `50 + 5/20 xx 8.75`

= `50 + (43.75)/20`

= 50 + 2.1875
= 52.1875

Q2 class = class containing `((2N)/4)^"th"` observation

∴ `(2N)/4 = (2 xx 111)/4` = 55.5
Cumulative frequency which is just greater than (or equal) to 55.5 is 69.
∴ Q2 lies in the class 55 – 60.
∴ L = 55, h = 5, f = 30, c.f. = 39

∴ Q = `L + h/f((2N)/4 - c.f.)`

= `55 + 5/30 (55.5 - 39)`

= `55 + 1/6 xx 16.5`

= 55 + 2.75
= 57.75

Q3 class = class containing `((3N)/4)^"th"` observation

∴ `(3N)/4 = (3 xx 111)/4` = 83.25
Cumulative frequency which is just greater than (or equal) to 83.25 is 89.
∴ Q3 lies in the class 60 – 65.
∴ L = 60, h = 5, f = 20, c.f. = 69

∴ Q = `L + h/f((3N)/4 - c.f.)`

= `60 + 5/20 (83.25 - 69)`

= `60 + 1/4 xx 14.25`

= 60 + 3.5625
= 63.5625
In order to find the number of persons between 57 kg and 72 kg,
We need to find x in Px, where Px = 57 kg and y in Py, where Py = 72 kg
Then (y – x) would be the % of persons weighing between 57 kg and 72 kg
Px = 57

∴ `L + h/f((x xx N)/100 - c.f.)` = 57

∴ `55 + 5/30 (1.11x - 39)` = 57

∴ `1/6(1.11x - 39)` = 57

∴ 1.11x – 39 = 12
∴ 1.11x = 51
∴ x = 45.95
∴ Px = 72

∴ `L + h/f((y xx N)/100 - c.f.)` = 72

∴ `70 + 5/8 (1.11y - 99)` = 72

∴ 0.625(1.11y − 99) = 72

∴ 1.11y – 99 = 3.2
∴ 1.11y = 102.2
∴ y = 92.07
∴ % of people weighing between 57 kg and 72 kg = 92.07 – 45.95 = 46.12 %
∴ No. of people weighing between 57 kg and 72 kg = 111 × 46.12% = 51.1932 ≈ 51

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Chapter 1: Partition Values - Miscellaneous Exercise 1 [Page 22]

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Balbharati Mathematics and Statistics 2 (Commerce) [English] 11 Standard Maharashtra State Board
Chapter 1 Partition Values
Miscellaneous Exercise 1 | Q 19 | Page 22
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