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Question
Using valence bond theory, explain the hybridisation and magnetic character of the following:
[Co(NH3)6]3+
Explain
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Solution
When ammonia acts as a ligand, it causes the electrons in the 3d orbitals to pair, freeing two 3d orbitals for hybridisation. As a result, the hybridisation is of the d2sp3 type.
Orbitals of Co:
| ↑ ↓ | ↑ ↓ | ↑ | ↑ | ↑ | ↑ ↓ | |||||
| 3d | 4s | 4p | ||||||||
d2sp3 hybridised orbitals of Co:
| ↑ ↓ | ↑ ↓ | ↑ ↓ | |||||||
| 3d | d2sp3 hybridisation | ||||||||
[Co(NH3)6]3+ (low spin complex):
| ↑ ↓ | ↑ ↓ | ↑ ↓ | XX | XX | XX | XX | XX | XX | |
| 3d | d2sp3 hybrid | ||||||||
Since all the electrons in the 3d orbitals are paired after the interaction with NH3 ligands, there are no unpaired electrons in the complex.
Therefore, [Co(NH3)6]3+ complex is diamagneticin nature.
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